hzbn.net
当前位置:首页>>关于(1-2/1)x(1-3/1)x(1-4/1)......(1-100/1)的资料>>

(1-2/1)x(1-3/1)x(1-4/1)......(1-100/1)

(1-1/2)x(1-1/3)x(1-1/4)......(1-1/100) =1/2x2/3x3/4x....x99/100 =1x(2/2)x(3/3)x(4/4)....x(99/99)x1/100 =1/100

(1+1/2)x(1+1/3)x(1+1/4)x...x(1+1/2011) =3/2×4/3×5/4×6/5×....×2015/2014 =2015/2=1007.5

(1+1/2+1/3+1/4)×(1/2+1/3+1/4+1/5)-(1+1/2+1/3+1/4+1/5)x(1/2+1/3+1/4) =(1/2+1/3+1/4+1/5)+(1/2+1/3+1/4)×(1/2+1/3+1/4+1/5)-(1/2+1/3+1/4)-(1/2+1/3+1/4+1/5)×(1/2+1/3+1/4) =(1/2+1/3+1/4+1/5)-(1/2+1/3+1/4) =1/5

解: 1/1X2+1/2X3+1/3X4+...+1/99X100 =(1-1/2)+(1/2-1/3)+(1/3-1/4)+...+(1/99-1/100) =1-1/2+1/2-1/3+1/3-1/4+...+1/99-1/100 (中间两项两项正负抵消) =1-1/100 =99/100

1/n-1/(n+1) 2009/2010

你的输入n是什么意思? 如果是计算 1-1/2+1/3-1/4+...+1/99-1/100 那么不需要输入n,其他不变就是了 如果是计算 1-1/2+1/3-1/4+...+1/n 才需要输入n 代码如下(不需要math.h头文件): #include void main(){ double sum; int i,n,m; //加个变量...

你好 解 1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)(x+4)+.....1/(x+2012)(x+2013) =[1/(x+1)-1/(x+2)]+[1/(x+2)-1/(x+3)]+[1/(x+3)-1/(x+4)]+.....+[1/(x+2012)-1/(x+2013)] =1/(x+1)-1/(x+2)+1/(x+2)-1/(x+3)+1/(x+3)-1/(x+4)+.....+1/(x+2012)-1/(x+...

g(x)=1-x+x²/2-x³/3+……-x^2013/2013 f(x)+3=0或g(x)-3=0 h(x)=f(x)+3=4+x-x²/2+x³/3-……+x^2013/2013 h'(x)=1-x+x^2-...........+x^2012 x=-1时,h'(1)=2013>0 -x≠1时,h'(x)=1-x+x^2-...........+x^2012=(-x)^2013-1]/[(-x)...

网站首页 | 网站地图
All rights reserved Powered by www.hzbn.net
copyright ©right 2010-2021。
内容来自网络,如有侵犯请联系客服。zhit325@qq.com